Friday, May 3, 2019

SS 7 - C - ROUND ROBIN (RR) SCHEDULING ALGORITHM

7 - Design, develop and implement a C/C++/Java program to simulate the working of Shortest remaining time and Round Robin (RR) scheduling algorithms. Experiment with different quantum sizes for RR algorithm.

lab7.c PROGRAM

// CPU Scheduling -Round Robin
#include<stdio.h>
struct process
{
char name;
int at,bt,wt,tt,rt;
int completed;
}p[10];

int n;
int q[10];  //queue
int front=-1,rear=-1;
void enqueue(int i)
{
    if(rear==10)
        printf("overflow");
    rear++;
    q[rear]=i;
    if(front==-1)
        front=0;
}

int dequeue()
{
    if(front==-1)
        printf("underflow");
    int temp=q[front];
    if(front==rear)
        front=rear=-1;
    else
        front++;
    return temp;
}

int isInQueue(int i)
{
    int k;
    for(k=front;k<=rear;k++)
    {
        if(q[k]==i)
        return 1;
    }
    return 0;
}

void sortByArrival()
{
    struct process temp;
    int i,j;
    for(i=0;i<n-1;i++)
    {
        for(j=i+1;j<n;j++)
        {
            if(p[i].at>p[j].at)
            {
                temp=p[i];
                p[i]=p[j];
                p[j]=temp;
            }
        }
    }
}

int main()
{
    int i,j,time=0,sum_bt=0,tq;
    char c;
    float avgwt=0;
     printf("Enter Number of Processes:\n");
     scanf("%d",&n);
     for(i=0,c='A';i<n;i++,c++)
     {
         p[i].name=c;
         printf("\nProcess %c\n",c);
         printf("\tArrival Time :");
         scanf("%d",&p[i].at);
         printf("\tBurst Time :");
         scanf("%d",&p[i].bt);
         p[i].rt=p[i].bt;
         p[i].completed=0;
         sum_bt+=p[i].bt;
    }
    printf("\nEnter the time quantum:");
    scanf("%d",&tq);
    sortByArrival();
    enqueue(0);
    printf("\nProcess execution order: ");
    for(time=p[0].at;time<sum_bt;)
    {
        i=dequeue();
        if(p[i].rt<=tq)
        {
            time+=p[i].rt;
            p[i].rt=0;
            p[i].completed=1;
            printf(" %c ",p[i].name);
            p[i].wt=time-p[i].at-p[i].bt;
            p[i].tt=time-p[i].at;
            for(j=0;j<n;j++)
            {
                if(p[j].at<=time && p[j].completed!=1&& isInQueue(j)!=1)
                {
                    enqueue(j);
                }
            }
        }
        else
        {
            time+=tq;
            p[i].rt-=tq;
            printf(" %c ",p[i].name);
            for(j=0;j<n;j++)
            {
                if(p[j].at<=time && p[j].completed!=1&&i!=j&& isInQueue(j)!=1)
                {
                    enqueue(j);
                }
            }
            enqueue(i);
        }
    }
    printf("\n\nName\tArrival Time\tBurst Time\tResponse Time\tTurnAround Time");
    for(i=0;i<n;i++)
    {
        avgwt+=p[i].wt;
        printf("\n%c\t\t%d\t\t%d\t\t%d\t\t%d",p[i].name,p[i].at,p[i].bt,p[i].wt,p[i].tt);
    }
    printf("\n\nAverage waiting time:%f",avgwt/n);
}


OUTPUT :( click on image to zoom )

1 comment:

  1. bro this is only for round robin can you please include shortest remaining time algo too

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